Base | Representation |
---|---|
bin | 10100101010101100000… |
… | …000110011110110001001 |
3 | 12000202211221002101111211 |
4 | 110222230000303312021 |
5 | 141232110111214233 |
6 | 3004235320453121 |
7 | 204415334114443 |
oct | 24525400636611 |
9 | 5022757071454 |
10 | 1420225101193 |
11 | 4a8350054158 |
12 | 1ab2ba61a1a1 |
13 | a3c07b17082 |
14 | 4ca4c769493 |
15 | 26e23a425cd |
hex | 14aac033d89 |
1420225101193 has 2 divisors, whose sum is σ = 1420225101194. Its totient is φ = 1420225101192.
The previous prime is 1420225101167. The next prime is 1420225101259. The reversal of 1420225101193 is 3911015220241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 771818475024 + 648406626169 = 878532^2 + 805237^2 .
It is a cyclic number.
It is not a de Polignac number, because 1420225101193 - 221 = 1420223004041 is a prime.
It is not a weakly prime, because it can be changed into another prime (1420225101103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710112550596 + 710112550597.
It is an arithmetic number, because the mean of its divisors is an integer number (710112550597).
Almost surely, 21420225101193 is an apocalyptic number.
It is an amenable number.
1420225101193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420225101193 is an equidigital number, since it uses as much as digits as its factorization.
1420225101193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 31.
The spelling of 1420225101193 in words is "one trillion, four hundred twenty billion, two hundred twenty-five million, one hundred one thousand, one hundred ninety-three".
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