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142025114137 is a prime number
BaseRepresentation
bin1000010001000101011…
…0110100001000011001
3111120120222022100002111
42010101112310020121
54311331412123022
6145125003032321
713155341360104
oct2042126641031
9446528270074
10142025114137
1155261524395
1223637b0b6a1
13105152c049a
146c3458373b
153a638e5477
hex21115b4219

142025114137 has 2 divisors, whose sum is σ = 142025114138. Its totient is φ = 142025114136.

The previous prime is 142025114131. The next prime is 142025114167. The reversal of 142025114137 is 731411520241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139514202256 + 2510911881 = 373516^2 + 50109^2 .

It is a cyclic number.

It is not a de Polignac number, because 142025114137 - 27 = 142025114009 is a prime.

It is a super-2 number, since 2×1420251141372 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142025114099 and 142025114108.

It is not a weakly prime, because it can be changed into another prime (142025114131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71012557068 + 71012557069.

It is an arithmetic number, because the mean of its divisors is an integer number (71012557069).

Almost surely, 2142025114137 is an apocalyptic number.

It is an amenable number.

142025114137 is a deficient number, since it is larger than the sum of its proper divisors (1).

142025114137 is an equidigital number, since it uses as much as digits as its factorization.

142025114137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 142025114137 its reverse (731411520241), we get a palindrome (873436634378).

The spelling of 142025114137 in words is "one hundred forty-two billion, twenty-five million, one hundred fourteen thousand, one hundred thirty-seven".