Base | Representation |
---|---|
bin | 10100101010101101100… |
… | …100111000100110010011 |
3 | 12000202220202110012121111 |
4 | 110222231210320212103 |
5 | 141232133320210214 |
6 | 3004242055034151 |
7 | 204416103106144 |
oct | 24525544704623 |
9 | 5022822405544 |
10 | 1420251335059 |
11 | 4a8363942037 |
12 | 1ab30736b957 |
13 | a3c103a0a7b |
14 | 4ca52037acb |
15 | 26e25ec55c4 |
hex | 14aad938993 |
1420251335059 has 2 divisors, whose sum is σ = 1420251335060. Its totient is φ = 1420251335058.
The previous prime is 1420251335051. The next prime is 1420251335117. The reversal of 1420251335059 is 9505331520241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1420251335059 - 23 = 1420251335051 is a prime.
It is a super-2 number, since 2×14202513350592 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1420251335051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710125667529 + 710125667530.
It is an arithmetic number, because the mean of its divisors is an integer number (710125667530).
Almost surely, 21420251335059 is an apocalyptic number.
1420251335059 is a deficient number, since it is larger than the sum of its proper divisors (1).
1420251335059 is an equidigital number, since it uses as much as digits as its factorization.
1420251335059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 1420251335059 in words is "one trillion, four hundred twenty billion, two hundred fifty-one million, three hundred thirty-five thousand, fifty-nine".
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