Base | Representation |
---|---|
bin | 100000010010110100010000… |
… | …000100000100100110110011 |
3 | 200121212222122202011021112222 |
4 | 200102310100010010212303 |
5 | 122104012023002424243 |
6 | 1222023533010511255 |
7 | 41626240155111125 |
oct | 4022642004044663 |
9 | 617788582137488 |
10 | 142030543014323 |
11 | 412898a6891827 |
12 | 13b1a57959552b |
13 | 61335659a27c2 |
14 | 271045a377215 |
15 | 1164818b06168 |
hex | 812d101049b3 |
142030543014323 has 2 divisors, whose sum is σ = 142030543014324. Its totient is φ = 142030543014322.
The previous prime is 142030543014293. The next prime is 142030543014391. The reversal of 142030543014323 is 323410345030241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142030543014323 - 210 = 142030543013299 is a prime.
It is not a weakly prime, because it can be changed into another prime (142030543014023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71015271507161 + 71015271507162.
It is an arithmetic number, because the mean of its divisors is an integer number (71015271507162).
Almost surely, 2142030543014323 is an apocalyptic number.
142030543014323 is a deficient number, since it is larger than the sum of its proper divisors (1).
142030543014323 is an equidigital number, since it uses as much as digits as its factorization.
142030543014323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 142030543014323 its reverse (323410345030241), we get a palindrome (465440888044564).
The spelling of 142030543014323 in words is "one hundred forty-two trillion, thirty billion, five hundred forty-three million, fourteen thousand, three hundred twenty-three".
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