14203103420041 has 4 divisors (see below), whose sum is σ = 14471086503492. Its totient is φ = 13935120336592.

The previous prime is 14203103420029. The next prime is 14203103420053. The reversal of 14203103420041 is 14002430130241.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14203103420029) and next prime (14203103420053).

It can be written as a sum of positive squares in 2 ways, for example, as 11343693441600 + 2859409978441 = 3368040^2 + 1690979^2 .

It is a cyclic number.

It is not a de Polignac number, because 14203103420041 - 2³⁷ = 14065664466569 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14203103419988 and 14203103420015.

It is not an unprimeable number, because it can be changed into a prime (14203103427041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133991541646 + ... + 133991541751.

It is an arithmetic number, because the mean of its divisors is an integer number (3617771625873).

Almost surely, 2^{14203103420041} is an apocalyptic number.

It is an amenable number.

14203103420041 is a deficient number, since it is larger than the sum of its proper divisors (267983083451).

14203103420041 is an equidigital number, since it uses as much as digits as its factorization.

14203103420041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267983083450.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14203103420041 its reverse (14002430130241), we get a palindrome (28205533550282).

The spelling of 14203103420041 in words is "fourteen trillion, two hundred three billion, one hundred three million, four hundred twenty thousand, forty-one".