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14203304232433 is a prime number
BaseRepresentation
bin1100111010101111011011…
…1001110100010111110001
31212021211012200201001000221
43032223312321310113301
53330201331340414213
650112524034213041
72664104055665221
oct316536671642761
955254180631027
1014203304232433
114586650a61598
121714841a24181
137c049a9a7a34
1437162d30c081
151996d94ae38d
hexceaf6e745f1

14203304232433 has 2 divisors, whose sum is σ = 14203304232434. Its totient is φ = 14203304232432.

The previous prime is 14203304232353. The next prime is 14203304232443. The reversal of 14203304232433 is 33423240330241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14132246266944 + 71057965489 = 3759288^2 + 266567^2 .

It is a cyclic number.

It is not a de Polignac number, because 14203304232433 - 241 = 12004280976881 is a prime.

It is a super-2 number, since 2×142033042324332 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14203304232443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101652116216 + 7101652116217.

It is an arithmetic number, because the mean of its divisors is an integer number (7101652116217).

Almost surely, 214203304232433 is an apocalyptic number.

It is an amenable number.

14203304232433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14203304232433 is an equidigital number, since it uses as much as digits as its factorization.

14203304232433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 34.

Adding to 14203304232433 its reverse (33423240330241), we get a palindrome (47626544562674).

The spelling of 14203304232433 in words is "fourteen trillion, two hundred three billion, three hundred four million, two hundred thirty-two thousand, four hundred thirty-three".