14203321211401 has 4 divisors (see below), whose sum is σ = 16232367098752. Its totient is φ = 12174275324052.

The previous prime is 14203321211363. The next prime is 14203321211449. The reversal of 14203321211401 is 10411212330241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14203321211401 - 2¹⁵ = 14203321178633 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14203321241401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1014522943665 + ... + 1014522943678.

It is an arithmetic number, because the mean of its divisors is an integer number (4058091774688).

Almost surely, 2^{14203321211401} is an apocalyptic number.

It is an amenable number.

14203321211401 is a deficient number, since it is larger than the sum of its proper divisors (2029045887351).

14203321211401 is an equidigital number, since it uses as much as digits as its factorization.

14203321211401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2029045887350.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14203321211401 its reverse (10411212330241), we get a palindrome (24614533541642).

The spelling of 14203321211401 in words is "fourteen trillion, two hundred three billion, three hundred twenty-one million, two hundred eleven thousand, four hundred one".