Base | Representation |
---|---|
bin | 100000010010111001110101… |
… | …110010000000111111100111 |
3 | 200121220120011000001120110220 |
4 | 200102321311302000333213 |
5 | 122104111320344234023 |
6 | 1222030404320015423 |
7 | 41626541661105504 |
oct | 4022716562007747 |
9 | 617816130046426 |
10 | 142036544524263 |
11 | 412913a6553aa4 |
12 | 13b1b773461573 |
13 | 6133cb117990c |
14 | 271086945a4ab |
15 | 1164a6a93b3e3 |
hex | 812e75c80fe7 |
142036544524263 has 32 divisors (see below), whose sum is σ = 196150364847360. Its totient is φ = 91314869184000.
The previous prime is 142036544524253. The next prime is 142036544524267. The reversal of 142036544524263 is 362425445630241.
142036544524263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 142036544524263 - 29 = 142036544523751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142036544524267) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 255528388 + ... + 256083638.
It is an arithmetic number, because the mean of its divisors is an integer number (6129698901480).
Almost surely, 2142036544524263 is an apocalyptic number.
142036544524263 is a deficient number, since it is larger than the sum of its proper divisors (54113820323097).
142036544524263 is a wasteful number, since it uses less digits than its factorization.
142036544524263 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 558847.
The product of its (nonzero) digits is 16588800, while the sum is 51.
The spelling of 142036544524263 in words is "one hundred forty-two trillion, thirty-six billion, five hundred forty-four million, five hundred twenty-four thousand, two hundred sixty-three".
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