Base | Representation |
---|---|
bin | 11010011101001111… |
… | …11101100101100011 |
3 | 1100122220022222210201 |
4 | 31032213331211203 |
5 | 213042211004421 |
6 | 10305241010031 |
7 | 1011663004333 |
oct | 151647754543 |
9 | 40586288721 |
10 | 14204000611 |
11 | 6029873989 |
12 | 2904a83917 |
13 | 14549670b8 |
14 | 98a61b0c3 |
15 | 581eccb91 |
hex | 34e9fd963 |
14204000611 has 2 divisors, whose sum is σ = 14204000612. Its totient is φ = 14204000610.
The previous prime is 14204000593. The next prime is 14204000617. The reversal of 14204000611 is 11600040241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14204000611 - 27 = 14204000483 is a prime.
It is not a weakly prime, because it can be changed into another prime (14204000617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102000305 + 7102000306.
It is an arithmetic number, because the mean of its divisors is an integer number (7102000306).
Almost surely, 214204000611 is an apocalyptic number.
14204000611 is a deficient number, since it is larger than the sum of its proper divisors (1).
14204000611 is an equidigital number, since it uses as much as digits as its factorization.
14204000611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 14204000611 its reverse (11600040241), we get a palindrome (25804040852).
The spelling of 14204000611 in words is "fourteen billion, two hundred four million, six hundred eleven", and thus it is an aban number.
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