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14204413014434 = 28385568753099
BaseRepresentation
bin1100111010110011100011…
…1111011111000110100010
31212021221001222001222222222
43032230320333133012202
53330211114212430214
650113230043231042
72664143411325626
oct316547077370642
955257058058888
1014204413014434
11458706a924955
121714ab1218482
137c0616611a66
143716d6695186
151997519cc38e
hexceb38fdf1a2

14204413014434 has 8 divisors (see below), whose sum is σ = 21563325781200. Its totient is φ = 7016637754036.

The previous prime is 14204413014347. The next prime is 14204413014439. The reversal of 14204413014434 is 43441031440241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 14204413014394 and 14204413014403.

It is not an unprimeable number, because it can be changed into a prime (14204413014439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42784376384 + ... + 42784376715.

It is an arithmetic number, because the mean of its divisors is an integer number (2695415722650).

Almost surely, 214204413014434 is an apocalyptic number.

14204413014434 is a deficient number, since it is larger than the sum of its proper divisors (7358912766766).

14204413014434 is an equidigital number, since it uses as much as digits as its factorization.

14204413014434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 85568753184.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 14204413014434 its reverse (43441031440241), we get a palindrome (57645444454675).

The spelling of 14204413014434 in words is "fourteen trillion, two hundred four billion, four hundred thirteen million, fourteen thousand, four hundred thirty-four".

Divisors: 1 2 83 166 85568753099 171137506198 7102206507217 14204413014434