14204414413131 has 4 divisors (see below), whose sum is σ = 18939219217512. Its totient is φ = 9469609608752.

The previous prime is 14204414413109. The next prime is 14204414413151. The reversal of 14204414413131 is 13131441440241.

14204414413131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14204414413131 - 2¹⁷ = 14204414282059 is a prime.

It is a super-2 number, since 2×14204414413131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14204414413092 and 14204414413101.

It is not an unprimeable number, because it can be changed into a prime (14204414413151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2367402402186 + ... + 2367402402191.

It is an arithmetic number, because the mean of its divisors is an integer number (4734804804378).

Almost surely, 2^{14204414413131} is an apocalyptic number.

14204414413131 is a deficient number, since it is larger than the sum of its proper divisors (4734804804381).

14204414413131 is an equidigital number, since it uses as much as digits as its factorization.

14204414413131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4734804804380.

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 14204414413131 its reverse (13131441440241), we get a palindrome (27335855853372).

The spelling of 14204414413131 in words is "fourteen trillion, two hundred four billion, four hundred fourteen million, four hundred thirteen thousand, one hundred thirty-one".