Base | Representation |
---|---|
bin | 11010011101011001… |
… | …11101111000101001 |
3 | 1100122222210122110011 |
4 | 31032230331320221 |
5 | 213043030000203 |
6 | 10305325051521 |
7 | 1012010110255 |
oct | 151654757051 |
9 | 40588718404 |
10 | 14205312553 |
11 | 602a58a633 |
12 | 29053b6ba1 |
13 | 14550062b3 |
14 | 98a87d265 |
15 | 58218b76d |
hex | 34eb3de29 |
14205312553 has 4 divisors (see below), whose sum is σ = 14205742480. Its totient is φ = 14204882628.
The previous prime is 14205312521. The next prime is 14205312593. The reversal of 14205312553 is 35521350241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14205312553 - 25 = 14205312521 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14205312503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160863 + ... + 232996.
It is an arithmetic number, because the mean of its divisors is an integer number (3551435620).
Almost surely, 214205312553 is an apocalyptic number.
It is an amenable number.
14205312553 is a deficient number, since it is larger than the sum of its proper divisors (429927).
14205312553 is an equidigital number, since it uses as much as digits as its factorization.
14205312553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429926.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 14205312553 its reverse (35521350241), we get a palindrome (49726662794).
The spelling of 14205312553 in words is "fourteen billion, two hundred five million, three hundred twelve thousand, five hundred fifty-three".
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