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14205312553 = 36067393859
BaseRepresentation
bin11010011101011001…
…11101111000101001
31100122222210122110011
431032230331320221
5213043030000203
610305325051521
71012010110255
oct151654757051
940588718404
1014205312553
11602a58a633
1229053b6ba1
1314550062b3
1498a87d265
1558218b76d
hex34eb3de29

14205312553 has 4 divisors (see below), whose sum is σ = 14205742480. Its totient is φ = 14204882628.

The previous prime is 14205312521. The next prime is 14205312593. The reversal of 14205312553 is 35521350241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14205312553 - 25 = 14205312521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14205312503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160863 + ... + 232996.

It is an arithmetic number, because the mean of its divisors is an integer number (3551435620).

Almost surely, 214205312553 is an apocalyptic number.

It is an amenable number.

14205312553 is a deficient number, since it is larger than the sum of its proper divisors (429927).

14205312553 is an equidigital number, since it uses as much as digits as its factorization.

14205312553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 429926.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 14205312553 its reverse (35521350241), we get a palindrome (49726662794).

The spelling of 14205312553 in words is "fourteen billion, two hundred five million, three hundred twelve thousand, five hundred fifty-three".

Divisors: 1 36067 393859 14205312553