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1420672125443 is a prime number
BaseRepresentation
bin10100101011000110101…
…010000100101000000011
312000211000002020120111112
4110223012222010220003
5141234014031003233
63004351530033535
7204432402551234
oct24530652045003
95024002216445
101420672125443
114a855a41808a
121ab4042788ab
13a3c7961146c
144ca91c9108b
1526e4cde4048
hex14ac6a84a03

1420672125443 has 2 divisors, whose sum is σ = 1420672125444. Its totient is φ = 1420672125442.

The previous prime is 1420672125421. The next prime is 1420672125491. The reversal of 1420672125443 is 3445212760241.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1420672125443 is a prime.

It is a super-2 number, since 2×14206721254432 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1420672125443.

It is not a weakly prime, because it can be changed into another prime (1420672125643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710336062721 + 710336062722.

It is an arithmetic number, because the mean of its divisors is an integer number (710336062722).

Almost surely, 21420672125443 is an apocalyptic number.

1420672125443 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420672125443 is an equidigital number, since it uses as much as digits as its factorization.

1420672125443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 322560, while the sum is 41.

Adding to 1420672125443 its reverse (3445212760241), we get a palindrome (4865884885684).

The spelling of 1420672125443 in words is "one trillion, four hundred twenty billion, six hundred seventy-two million, one hundred twenty-five thousand, four hundred forty-three".