Search a number
-
+
1421132403 = 3473710801
BaseRepresentation
bin101010010110100…
…1100001001110011
310200001010000011110
41110231030021303
510402302214103
6353003444403
750134266105
oct12455141163
93601100143
101421132403
1166a212899
12337b26703
1319856a462
14d6a53575
1584b6b403
hex54b4c273

1421132403 has 4 divisors (see below), whose sum is σ = 1894843208. Its totient is φ = 947421600.

The previous prime is 1421132381. The next prime is 1421132429. The reversal of 1421132403 is 3042311241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1421132403 - 210 = 1421131379 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1421132403.

It is not an unprimeable number, because it can be changed into a prime (1421132483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236855398 + ... + 236855403.

It is an arithmetic number, because the mean of its divisors is an integer number (473710802).

Almost surely, 21421132403 is an apocalyptic number.

1421132403 is a deficient number, since it is larger than the sum of its proper divisors (473710805).

1421132403 is an equidigital number, since it uses as much as digits as its factorization.

1421132403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 473710804.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1421132403 is about 37697.9097961677. The cubic root of 1421132403 is about 1124.2895670639.

Adding to 1421132403 its reverse (3042311241), we get a palindrome (4463443644).

The spelling of 1421132403 in words is "one billion, four hundred twenty-one million, one hundred thirty-two thousand, four hundred three".

Divisors: 1 3 473710801 1421132403