Base | Representation |
---|---|
bin | 11010011110000111… |
… | …11100010011101001 |
3 | 1100200102010122020121 |
4 | 31033003330103221 |
5 | 213101100213101 |
6 | 10310102123241 |
7 | 1012112233504 |
oct | 151703742351 |
9 | 40612118217 |
10 | 14211335401 |
11 | 6032a2369a |
12 | 2907420521 |
13 | 1456334803 |
14 | 98b5aa13b |
15 | 58297b0a1 |
hex | 34f0fc4e9 |
14211335401 has 2 divisors, whose sum is σ = 14211335402. Its totient is φ = 14211335400.
The previous prime is 14211335389. The next prime is 14211335429. The reversal of 14211335401 is 10453311241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12072735376 + 2138600025 = 109876^2 + 46245^2 .
It is an emirp because it is prime and its reverse (10453311241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14211335401 - 27 = 14211335273 is a prime.
It is not a weakly prime, because it can be changed into another prime (14211735401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7105667700 + 7105667701.
It is an arithmetic number, because the mean of its divisors is an integer number (7105667701).
Almost surely, 214211335401 is an apocalyptic number.
It is an amenable number.
14211335401 is a deficient number, since it is larger than the sum of its proper divisors (1).
14211335401 is an equidigital number, since it uses as much as digits as its factorization.
14211335401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 14211335401 its reverse (10453311241), we get a palindrome (24664646642).
The spelling of 14211335401 in words is "fourteen billion, two hundred eleven million, three hundred thirty-five thousand, four hundred one".
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