142113431131 has 4 divisors (see below), whose sum is σ = 162415349872. Its totient is φ = 121811512392.

The previous prime is 142113431123. The next prime is 142113431153. The reversal of 142113431131 is 131134311241.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131134311241 = 467 ⋅280801523.

It is a cyclic number.

It is not a de Polignac number, because 142113431131 - 2³ = 142113431123 is a prime.

It is a super-2 number, since 2×142113431131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142113431096 and 142113431105.

It is not an unprimeable number, because it can be changed into a prime (142113431101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10150959360 + ... + 10150959373.

It is an arithmetic number, because the mean of its divisors is an integer number (40603837468).

Almost surely, 2^142113431131 is an apocalyptic number.

142113431131 is a deficient number, since it is larger than the sum of its proper divisors (20301918741).

142113431131 is an equidigital number, since it uses as much as digits as its factorization.

142113431131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20301918740.

The product of its digits is 864, while the sum is 25.

Adding to 142113431131 its reverse (131134311241), we get a palindrome (273247742372).

The spelling of 142113431131 in words is "one hundred forty-two billion, one hundred thirteen million, four hundred thirty-one thousand, one hundred thirty-one".