14211345042 has 12 divisors (see below), whose sum is σ = 30791247630. Its totient is φ = 4737115008.

The previous prime is 14211344999. The next prime is 14211345073. The reversal of 14211345042 is 24054311241.

14211345042 is a `hidden beast` number, since 1 + 4 + 21 + 134 + 504 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 10134650241 + 4076694801 = 100671^2 + 63849^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14211344997 and 14211345015.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 394759567 + ... + 394759602.

Almost surely, 2^14211345042 is an apocalyptic number.

14211345042 is an abundant number, since it is smaller than the sum of its proper divisors (16579902588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14211345042 is a wasteful number, since it uses less digits than its factorization.

14211345042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 789519177 (or 789519174 counting only the distinct ones).

The product of its (nonzero) digits is 3840, while the sum is 27.

Adding to 14211345042 its reverse (24054311241), we get a palindrome (38265656283).

The spelling of 14211345042 in words is "fourteen billion, two hundred eleven million, three hundred forty-five thousand, forty-two".