Search a number
-
+
1421144411233 is a prime number
BaseRepresentation
bin10100101011100010110…
…011101100110001100001
312000212012222221011210211
4110223202303230301201
5141241000432124413
63004510440454121
7204450166116601
oct24534263546141
95025188834724
101421144411233
114a8781a75418
121ab51647a341
13a4023411b01
144cad88b0c01
1526e795d583d
hex14ae2cecc61

1421144411233 has 2 divisors, whose sum is σ = 1421144411234. Its totient is φ = 1421144411232.

The previous prime is 1421144411227. The next prime is 1421144411261. The reversal of 1421144411233 is 3321144411241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 939769319889 + 481375091344 = 969417^2 + 693812^2 .

It is an emirp because it is prime and its reverse (3321144411241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1421144411233 - 217 = 1421144280161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1421144411195 and 1421144411204.

It is not a weakly prime, because it can be changed into another prime (1421144411293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710572205616 + 710572205617.

It is an arithmetic number, because the mean of its divisors is an integer number (710572205617).

Almost surely, 21421144411233 is an apocalyptic number.

It is an amenable number.

1421144411233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421144411233 is an equidigital number, since it uses as much as digits as its factorization.

1421144411233 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9216, while the sum is 31.

Adding to 1421144411233 its reverse (3321144411241), we get a palindrome (4742288822474).

The spelling of 1421144411233 in words is "one trillion, four hundred twenty-one billion, one hundred forty-four million, four hundred eleven thousand, two hundred thirty-three".