Base | Representation |
---|---|
bin | 100000010100001000111001… |
… | …100010101000010110011010 |
3 | 200122012200021001002022111212 |
4 | 200110020321202220112122 |
5 | 122112004143400012442 |
6 | 1222133403551023122 |
7 | 41635635414014201 |
oct | 4024107142502632 |
9 | 618180231068455 |
10 | 142121433204122 |
11 | 413143a7a44669 |
12 | 13b3410450aaa2 |
13 | 613bcbc0650b8 |
14 | 27149dd59a238 |
15 | 1166d881c2a82 |
hex | 8142398a859a |
142121433204122 has 4 divisors (see below), whose sum is σ = 213182149806186. Its totient is φ = 71060716602060.
The previous prime is 142121433204041. The next prime is 142121433204199. The reversal of 142121433204122 is 221402334121241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 111360089347441 + 30761343856681 = 10552729^2 + 5546291^2 .
It is a super-2 number, since 2×1421214332041222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35530358301029 + ... + 35530358301032.
Almost surely, 2142121433204122 is an apocalyptic number.
142121433204122 is a deficient number, since it is larger than the sum of its proper divisors (71060716602064).
142121433204122 is an equidigital number, since it uses as much as digits as its factorization.
142121433204122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71060716602063.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 142121433204122 its reverse (221402334121241), we get a palindrome (363523767325363).
The spelling of 142121433204122 in words is "one hundred forty-two trillion, one hundred twenty-one billion, four hundred thirty-three million, two hundred four thousand, one hundred twenty-two".
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