Base | Representation |
---|---|
bin | 1100111011010001010101… |
… | …0000000110010011010010 |
3 | 1212022200200211020210021112 |
4 | 3032310111100012103102 |
5 | 3330324000222332424 |
6 | 50121030555253322 |
7 | 2664545413666262 |
oct | 316642520062322 |
9 | 55280624223245 |
10 | 14212403324114 |
11 | 458a4a0183876 |
12 | 171656114a242 |
13 | 7c12bab41258 |
14 | 371c539597a2 |
15 | 199a6d21160e |
hex | ced154064d2 |
14212403324114 has 8 divisors (see below), whose sum is σ = 21318872479740. Its totient is φ = 7106112497536.
The previous prime is 14212403324111. The next prime is 14212403324123. The reversal of 14212403324114 is 41142330421241.
It can be written as a sum of positive squares in 2 ways, for example, as 13113690566089 + 1098712758025 = 3621283^2 + 1048195^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (14212403324111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44382839 + ... + 44701914.
Almost surely, 214212403324114 is an apocalyptic number.
14212403324114 is a deficient number, since it is larger than the sum of its proper divisors (7106469155626).
14212403324114 is an equidigital number, since it uses as much as digits as its factorization.
14212403324114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89164524.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 14212403324114 its reverse (41142330421241), we get a palindrome (55354733745355).
The spelling of 14212403324114 in words is "fourteen trillion, two hundred twelve billion, four hundred three million, three hundred twenty-four thousand, one hundred fourteen".
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