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14212444303003 = 89159690385427
BaseRepresentation
bin1100111011010001011110…
…1100011010111010011011
31212022200210200100201202011
43032310113230122322123
53330324041220144003
650121035021450351
72664546422212252
oct316642754327233
955280720321664
1014212444303003
11458a511322921
121716572a109b7
137c12c648b50b
14371c59185799
15199a71b0846d
hexced17b1ae9b

14212444303003 has 4 divisors (see below), whose sum is σ = 14372134688520. Its totient is φ = 14052753917488.

The previous prime is 14212444302971. The next prime is 14212444303009. The reversal of 14212444303003 is 30030344421241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14212444303003 - 25 = 14212444302971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14212444303009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79845192625 + ... + 79845192802.

It is an arithmetic number, because the mean of its divisors is an integer number (3593033672130).

Almost surely, 214212444303003 is an apocalyptic number.

14212444303003 is a deficient number, since it is larger than the sum of its proper divisors (159690385517).

14212444303003 is an equidigital number, since it uses as much as digits as its factorization.

14212444303003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159690385516.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 14212444303003 its reverse (30030344421241), we get a palindrome (44242788724244).

The spelling of 14212444303003 in words is "fourteen trillion, two hundred twelve billion, four hundred forty-four million, three hundred three thousand, three".

Divisors: 1 89 159690385427 14212444303003