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14212586473091 is a prime number
BaseRepresentation
bin1100111011010010000000…
…1010110000011010000011
31212022201011120212201102222
43032310200022300122003
53330324334114114331
650121101101001255
72664553066511306
oct316644012603203
955281146781388
1014212586473091
11458a5845a7366
1217165b255322b
137c1319a78526
14371c6ddd2b3d
15199a7e33cb7b
hexced202b0683

14212586473091 has 2 divisors, whose sum is σ = 14212586473092. Its totient is φ = 14212586473090.

The previous prime is 14212586473069. The next prime is 14212586473097. The reversal of 14212586473091 is 19037468521241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14212586473091 - 222 = 14212582278787 is a prime.

It is a super-2 number, since 2×142125864730912 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14212586473097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106293236545 + 7106293236546.

It is an arithmetic number, because the mean of its divisors is an integer number (7106293236546).

It is a 1-persistent number, because it is pandigital, but 2⋅14212586473091 = 28425172946182 is not.

Almost surely, 214212586473091 is an apocalyptic number.

14212586473091 is a deficient number, since it is larger than the sum of its proper divisors (1).

14212586473091 is an equidigital number, since it uses as much as digits as its factorization.

14212586473091 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 14212586473091 in words is "fourteen trillion, two hundred twelve billion, five hundred eighty-six million, four hundred seventy-three thousand, ninety-one".