Base | Representation |
---|---|
bin | 1100111011010010000000… |
… | …1010110000011010000011 |
3 | 1212022201011120212201102222 |
4 | 3032310200022300122003 |
5 | 3330324334114114331 |
6 | 50121101101001255 |
7 | 2664553066511306 |
oct | 316644012603203 |
9 | 55281146781388 |
10 | 14212586473091 |
11 | 458a5845a7366 |
12 | 17165b255322b |
13 | 7c1319a78526 |
14 | 371c6ddd2b3d |
15 | 199a7e33cb7b |
hex | ced202b0683 |
14212586473091 has 2 divisors, whose sum is σ = 14212586473092. Its totient is φ = 14212586473090.
The previous prime is 14212586473069. The next prime is 14212586473097. The reversal of 14212586473091 is 19037468521241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14212586473091 - 222 = 14212582278787 is a prime.
It is a super-2 number, since 2×142125864730912 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14212586473097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106293236545 + 7106293236546.
It is an arithmetic number, because the mean of its divisors is an integer number (7106293236546).
It is a 1-persistent number, because it is pandigital, but 2⋅14212586473091 = 28425172946182 is not.
Almost surely, 214212586473091 is an apocalyptic number.
14212586473091 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212586473091 is an equidigital number, since it uses as much as digits as its factorization.
14212586473091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2903040, while the sum is 53.
The spelling of 14212586473091 in words is "fourteen trillion, two hundred twelve billion, five hundred eighty-six million, four hundred seventy-three thousand, ninety-one".
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