Base | Representation |
---|---|
bin | 100000010100010001001101… |
… | …001110011110100110101010 |
3 | 200122020112021201000020011122 |
4 | 200110101031032132212222 |
5 | 122112130430432301414 |
6 | 1222141441041455242 |
7 | 41636402440306643 |
oct | 4024211516364652 |
9 | 618215251006148 |
10 | 142130353400234 |
11 | 41318165188a71 |
12 | 13b35993941522 |
13 | 613cab1123354 |
14 | 271520815a6ca |
15 | 116720b388b8e |
hex | 81444d39e9aa |
142130353400234 has 8 divisors (see below), whose sum is σ = 213197836216320. Its totient is φ = 71064407994796.
The previous prime is 142130353400213. The next prime is 142130353400291. The reversal of 142130353400234 is 432004353031241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 142130353400194 and 142130353400203.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 384121514 + ... + 384491349.
It is an arithmetic number, because the mean of its divisors is an integer number (26649729527040).
Almost surely, 2142130353400234 is an apocalyptic number.
142130353400234 is a deficient number, since it is larger than the sum of its proper divisors (71067482816086).
142130353400234 is an equidigital number, since it uses as much as digits as its factorization.
142130353400234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 768705324.
The product of its (nonzero) digits is 103680, while the sum is 35.
The spelling of 142130353400234 in words is "one hundred forty-two trillion, one hundred thirty billion, three hundred fifty-three million, four hundred thousand, two hundred thirty-four".
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