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142131010499 is a prime number
BaseRepresentation
bin1000010001011110101…
…0110001101111000011
3111120212100120102120222
42010113222301233003
54312041014313444
6145143304453255
713161065440622
oct2042752615703
9446770512528
10142131010499
1155306282945
122366747a22b
1310531219a5a
146c4466b6b9
153a6cd61eee
hex2117ab1bc3

142131010499 has 2 divisors, whose sum is σ = 142131010500. Its totient is φ = 142131010498.

The previous prime is 142131010421. The next prime is 142131010513. The reversal of 142131010499 is 994010131241.

142131010499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (994010131241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142131010499 - 236 = 73411533763 is a prime.

It is a super-3 number, since 3×1421310104993 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (142133010499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065505249 + 71065505250.

It is an arithmetic number, because the mean of its divisors is an integer number (71065505250).

Almost surely, 2142131010499 is an apocalyptic number.

142131010499 is a deficient number, since it is larger than the sum of its proper divisors (1).

142131010499 is an equidigital number, since it uses as much as digits as its factorization.

142131010499 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 35.

The spelling of 142131010499 in words is "one hundred forty-two billion, one hundred thirty-one million, ten thousand, four hundred ninety-nine".