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1421310342211 = 8263172008997
BaseRepresentation
bin10100101011101100101…
…100101011010001000011
312000212122120011100022121
4110223230230223101003
5141241320421422321
63004535125145111
7204454252400434
oct24535454532103
95025576140277
101421310342211
114a88576a8861
121ab561b5b197
13a404b8cb016
144cb1294548b
1526e88e60441
hex14aecb2b443

1421310342211 has 4 divisors (see below), whose sum is σ = 1421482359472. Its totient is φ = 1421138324952.

The previous prime is 1421310342203. The next prime is 1421310342217. The reversal of 1421310342211 is 1122430131241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1421310342211 - 23 = 1421310342203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1421310342217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85996236 + ... + 86012761.

It is an arithmetic number, because the mean of its divisors is an integer number (355370589868).

Almost surely, 21421310342211 is an apocalyptic number.

1421310342211 is a deficient number, since it is larger than the sum of its proper divisors (172017261).

1421310342211 is an equidigital number, since it uses as much as digits as its factorization.

1421310342211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172017260.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1421310342211 its reverse (1122430131241), we get a palindrome (2543740473452).

The spelling of 1421310342211 in words is "one trillion, four hundred twenty-one billion, three hundred ten million, three hundred forty-two thousand, two hundred eleven".

Divisors: 1 8263 172008997 1421310342211