Base | Representation |
---|---|
bin | 1100111011010011111100… |
… | …0000111101110000000010 |
3 | 1212022202111122200210220100 |
4 | 3032310333000331300002 |
5 | 3330331414111000002 |
6 | 50121224305223230 |
7 | 2664601652434155 |
oct | 316647700756002 |
9 | 55282448623810 |
10 | 14213104000002 |
11 | 458a81a744a56 |
12 | 1716717931b16 |
13 | 7c13a005917b |
14 | 371cbca2bc9c |
15 | 199aae9b911c |
hex | ced3f03dc02 |
14213104000002 has 24 divisors (see below), whose sum is σ = 31627357551036. Its totient is φ = 4609655351136.
The previous prime is 14213103999931. The next prime is 14213104000021. The reversal of 14213104000002 is 20000040131241.
14213104000002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 13891863298041 + 321240701961 = 3727179^2 + 566781^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10670497833 + ... + 10670499164.
Almost surely, 214213104000002 is an apocalyptic number.
14213104000002 is an abundant number, since it is smaller than the sum of its proper divisors (17414253551034).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14213104000002 is a wasteful number, since it uses less digits than its factorization.
14213104000002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21340997042 (or 21340997039 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 14213104000002 its reverse (20000040131241), we get a palindrome (34213144131243).
The spelling of 14213104000002 in words is "fourteen trillion, two hundred thirteen billion, one hundred four million, two", and thus it is an aban number.
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