Base | Representation |
---|---|
bin | 11010011110010101… |
… | …10001000010010001 |
3 | 1100200112111112001221 |
4 | 31033022301002101 |
5 | 213102024433431 |
6 | 10310204325041 |
7 | 1012133364001 |
oct | 151712610221 |
9 | 40615445057 |
10 | 14213124241 |
11 | 6033a35678 |
12 | 2907b43781 |
13 | 145680cab4 |
14 | 98b914001 |
15 | 582bd1111 |
hex | 34f2b1091 |
14213124241 has 4 divisors (see below), whose sum is σ = 14597262772. Its totient is φ = 13828985712.
The previous prime is 14213124169. The next prime is 14213124269. The reversal of 14213124241 is 14242131241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7173243025 + 7039881216 = 84695^2 + 83904^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213124241 - 217 = 14212993169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14213124281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192069210 + ... + 192069283.
It is an arithmetic number, because the mean of its divisors is an integer number (3649315693).
Almost surely, 214213124241 is an apocalyptic number.
It is an amenable number.
14213124241 is a deficient number, since it is larger than the sum of its proper divisors (384138531).
14213124241 is an equidigital number, since it uses as much as digits as its factorization.
14213124241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 384138530.
The product of its digits is 1536, while the sum is 25.
Adding to 14213124241 its reverse (14242131241), we get a palindrome (28455255482).
The spelling of 14213124241 in words is "fourteen billion, two hundred thirteen million, one hundred twenty-four thousand, two hundred forty-one".
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