14213233342441 has 4 divisors (see below), whose sum is σ = 16243695248512. Its totient is φ = 12182771436372.

The previous prime is 14213233342439. The next prime is 14213233342487. The reversal of 14213233342441 is 14424333231241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14213233342441 - 2¹ = 14213233342439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14213233342441.

It is not an unprimeable number, because it can be changed into a prime (14213233342241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1015230953025 + ... + 1015230953038.

It is an arithmetic number, because the mean of its divisors is an integer number (4060923812128).

Almost surely, 2^{14213233342441} is an apocalyptic number.

It is an amenable number.

14213233342441 is a deficient number, since it is larger than the sum of its proper divisors (2030461906071).

14213233342441 is an equidigital number, since it uses as much as digits as its factorization.

14213233342441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2030461906070.

The product of its digits is 165888, while the sum is 37.

Adding to 14213233342441 its reverse (14424333231241), we get a palindrome (28637566573682).

The spelling of 14213233342441 in words is "fourteen trillion, two hundred thirteen billion, two hundred thirty-three million, three hundred forty-two thousand, four hundred forty-one".