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14213245753 = 72030463679
BaseRepresentation
bin11010011110010110…
…01110101100111001
31100200112201200202101
431033023032230321
5213102042331003
610310211103401
71012134411160
oct151713165471
940615650671
1014213245753
1160340089a3
122907ba1b61
1314568531b5
1498b9463d7
15582c0711d
hex34f2ceb39

14213245753 has 4 divisors (see below), whose sum is σ = 16243709440. Its totient is φ = 12182782068.

The previous prime is 14213245751. The next prime is 14213245819. The reversal of 14213245753 is 35754231241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14213245753 - 21 = 14213245751 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14213245751) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1015231833 + ... + 1015231846.

It is an arithmetic number, because the mean of its divisors is an integer number (4060927360).

Almost surely, 214213245753 is an apocalyptic number.

It is an amenable number.

14213245753 is a deficient number, since it is larger than the sum of its proper divisors (2030463687).

14213245753 is an equidigital number, since it uses as much as digits as its factorization.

14213245753 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2030463686.

The product of its digits is 100800, while the sum is 37.

Adding to 14213245753 its reverse (35754231241), we get a palindrome (49967476994).

The spelling of 14213245753 in words is "fourteen billion, two hundred thirteen million, two hundred forty-five thousand, seven hundred fifty-three".

Divisors: 1 7 2030463679 14213245753