Base | Representation |
---|---|
bin | 1100111011010100110010… |
… | …1010100001111101111011 |
3 | 1212022210002121121012220221 |
4 | 3032311030222201331323 |
5 | 3330332401222000214 |
6 | 50121303125400511 |
7 | 2664610433053624 |
oct | 316651452417573 |
9 | 55283077535827 |
10 | 14213333000059 |
11 | 458a927a350a6 |
12 | 1716780569137 |
13 | 7c140862826b |
14 | 371d011dca4b |
15 | 199ac4b50e24 |
hex | ced4caa1f7b |
14213333000059 has 2 divisors, whose sum is σ = 14213333000060. Its totient is φ = 14213333000058.
The previous prime is 14213332999973. The next prime is 14213333000089. The reversal of 14213333000059 is 95000033331241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14213333000059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14213332999988 and 14213333000033.
It is not a weakly prime, because it can be changed into another prime (14213333000089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106666500029 + 7106666500030.
It is an arithmetic number, because the mean of its divisors is an integer number (7106666500030).
Almost surely, 214213333000059 is an apocalyptic number.
14213333000059 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213333000059 is an equidigital number, since it uses as much as digits as its factorization.
14213333000059 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 34.
The spelling of 14213333000059 in words is "fourteen trillion, two hundred thirteen billion, three hundred thirty-three million, fifty-nine", and thus it is an aban number.
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