14213412114001 has 2 divisors, whose sum is σ = 14213412114002. Its totient is φ = 14213412114000.

The previous prime is 14213412113933. The next prime is 14213412114017. The reversal of 14213412114001 is 10041121431241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13097515664401 + 1115896449600 = 3619049^2 + 1056360^2 .

It is an emirp because it is prime and its reverse (10041121431241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14213412114001 - 2²⁹ = 14212875243089 is a prime.

It is not a weakly prime, because it can be changed into another prime (14213412112001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106706057000 + 7106706057001.

It is an arithmetic number, because the mean of its divisors is an integer number (7106706057001).

Almost surely, 2^{14213412114001} is an apocalyptic number.

It is an amenable number.

14213412114001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213412114001 is an equidigital number, since it uses as much as digits as its factorization.

14213412114001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14213412114001 its reverse (10041121431241), we get a palindrome (24254533545242).

The spelling of 14213412114001 in words is "fourteen trillion, two hundred thirteen billion, four hundred twelve million, one hundred fourteen thousand, one".