14213422410001 has 4 divisors (see below), whose sum is σ = 14213436005104. Its totient is φ = 14213408814900.

The previous prime is 14213422409959. The next prime is 14213422410023. The reversal of 14213422410001 is 10001422431241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14213422410001 - 2¹¹ = 14213422407953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14213422410601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5085615 + ... + 7368196.

It is an arithmetic number, because the mean of its divisors is an integer number (3553359001276).

Almost surely, 2^{14213422410001} is an apocalyptic number.

It is an amenable number.

14213422410001 is a deficient number, since it is larger than the sum of its proper divisors (13595103).

14213422410001 is a wasteful number, since it uses less digits than its factorization.

14213422410001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13595102.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 14213422410001 its reverse (10001422431241), we get a palindrome (24214844841242).

The spelling of 14213422410001 in words is "fourteen trillion, two hundred thirteen billion, four hundred twenty-two million, four hundred ten thousand, one".