Base | Representation |
---|---|
bin | 1100111011010101111010… |
… | …0011011100001011101001 |
3 | 1212022210212112100110111122 |
4 | 3032311132203130023221 |
5 | 3330334010040144431 |
6 | 50121353010305025 |
7 | 2664621036120635 |
oct | 316653643341351 |
9 | 55283775313448 |
10 | 14213633131241 |
11 | 458aa713990a5 |
12 | 1716844b88175 |
13 | 7c145587098b |
14 | 371d2d007dc5 |
15 | 199ae1188a7b |
hex | ced5e8dc2e9 |
14213633131241 has 2 divisors, whose sum is σ = 14213633131242. Its totient is φ = 14213633131240.
The previous prime is 14213633131189. The next prime is 14213633131277. The reversal of 14213633131241 is 14213133631241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11639867475625 + 2573765655616 = 3411725^2 + 1604296^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213633131241 - 226 = 14213566022377 is a prime.
It is not a weakly prime, because it can be changed into another prime (14213653131241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106816565620 + 7106816565621.
It is an arithmetic number, because the mean of its divisors is an integer number (7106816565621).
Almost surely, 214213633131241 is an apocalyptic number.
It is an amenable number.
14213633131241 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213633131241 is an equidigital number, since it uses as much as digits as its factorization.
14213633131241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 35.
Adding to 14213633131241 its reverse (14213133631241), we get a palindrome (28426766762482).
The spelling of 14213633131241 in words is "fourteen trillion, two hundred thirteen billion, six hundred thirty-three million, one hundred thirty-one thousand, two hundred forty-one".
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