1421366631241 has 4 divisors (see below), whose sum is σ = 1421462794752. Its totient is φ = 1421270467732.

The previous prime is 1421366631227. The next prime is 1421366631257.

1421366631241 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1421366631241 - 2³³ = 1412776696649 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1421366631194 and 1421366631203.

It is not an unprimeable number, because it can be changed into a prime (1421366631941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48059581 + ... + 48089146.

It is an arithmetic number, because the mean of its divisors is an integer number (355365698688).

Almost surely, 2^{1421366631241} is an apocalyptic number.

It is an amenable number.

1421366631241 is a deficient number, since it is larger than the sum of its proper divisors (96163511).

1421366631241 is an equidigital number, since it uses as much as digits as its factorization.

1421366631241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96163510.

The product of its digits is 124416, while the sum is 40.

The spelling of 1421366631241 in words is "one trillion, four hundred twenty-one billion, three hundred sixty-six million, six hundred thirty-one thousand, two hundred forty-one".