Base | Representation |
---|---|
bin | 1100111011010111010101… |
… | …0101011011101111001011 |
3 | 1212022211212011112110000011 |
4 | 3032311311111123233023 |
5 | 3330340300411212441 |
6 | 50121454542252351 |
7 | 2664633356603455 |
oct | 316656525335713 |
9 | 55284764473004 |
10 | 14214015335371 |
11 | 4590148109785 |
12 | 1716930b870b7 |
13 | 7c14b6ac1177 |
14 | 371d67a992d5 |
15 | 199b149d4581 |
hex | ced7555bbcb |
14214015335371 has 2 divisors, whose sum is σ = 14214015335372. Its totient is φ = 14214015335370.
The previous prime is 14214015335341. The next prime is 14214015335449. The reversal of 14214015335371 is 17353351041241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14214015335371 - 233 = 14205425400779 is a prime.
It is not a weakly prime, because it can be changed into another prime (14214015335341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107007667685 + 7107007667686.
It is an arithmetic number, because the mean of its divisors is an integer number (7107007667686).
Almost surely, 214214015335371 is an apocalyptic number.
14214015335371 is a deficient number, since it is larger than the sum of its proper divisors (1).
14214015335371 is an equidigital number, since it uses as much as digits as its factorization.
14214015335371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 14214015335371 in words is "fourteen trillion, two hundred fourteen billion, fifteen million, three hundred thirty-five thousand, three hundred seventy-one".
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