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142140220033 = 7210151285767
BaseRepresentation
bin1000010001100000110…
…1111010001010000001
3111120212222220022200211
42010120031322022001
54312100344020113
6145144234114121
713161236635600
oct2043015721201
9446788808624
10142140220033
11553104a3129
122366a57b941
13105330c2896
146c45987a37
153a6da80b3d
hex211837a281

142140220033 has 12 divisors (see below), whose sum is σ = 165363653952. Its totient is φ = 121822045800.

The previous prime is 142140219943. The next prime is 142140220043. The reversal of 142140220033 is 330022041241.

It is not a de Polignac number, because 142140220033 - 213 = 142140211841 is a prime.

It is a super-3 number, since 3×1421402200333 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142140219986 and 142140220013.

It is not an unprimeable number, because it can be changed into a prime (142140220043) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 354516 + ... + 640282.

It is an arithmetic number, because the mean of its divisors is an integer number (13780304496).

Almost surely, 2142140220033 is an apocalyptic number.

It is an amenable number.

142140220033 is a deficient number, since it is larger than the sum of its proper divisors (23223433919).

142140220033 is a wasteful number, since it uses less digits than its factorization.

142140220033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 295932 (or 295925 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 142140220033 its reverse (330022041241), we get a palindrome (472162261274).

The spelling of 142140220033 in words is "one hundred forty-two billion, one hundred forty million, two hundred twenty thousand, thirty-three".

Divisors: 1 7 49 10151 71057 285767 497399 2000369 14002583 2900820817 20305745719 142140220033