Base | Representation |
---|---|
bin | 10100101011110010010… |
… | …100010111100000100011 |
3 | 12000212220010120211010121 |
4 | 110223302110113200203 |
5 | 141242014041224443 |
6 | 3004552334141111 |
7 | 204456506014156 |
oct | 24536224274043 |
9 | 5025803524117 |
10 | 1421404633123 |
11 | 4a88a594aa32 |
12 | 1ab589651797 |
13 | a40652c3067 |
14 | 4cb2128bc9d |
15 | 26e923884ed |
hex | 14af2517823 |
1421404633123 has 2 divisors, whose sum is σ = 1421404633124. Its totient is φ = 1421404633122.
The previous prime is 1421404633093. The next prime is 1421404633127. The reversal of 1421404633123 is 3213364041241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1421404633123 - 25 = 1421404633091 is a prime.
It is a super-2 number, since 2×14214046331232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1421404633127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710702316561 + 710702316562.
It is an arithmetic number, because the mean of its divisors is an integer number (710702316562).
Almost surely, 21421404633123 is an apocalyptic number.
1421404633123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421404633123 is an equidigital number, since it uses as much as digits as its factorization.
1421404633123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 1421404633123 its reverse (3213364041241), we get a palindrome (4634768674364).
The spelling of 1421404633123 in words is "one trillion, four hundred twenty-one billion, four hundred four million, six hundred thirty-three thousand, one hundred twenty-three".
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