Base | Representation |
---|---|
bin | 1100111011010111101100… |
… | …0110001100010010100001 |
3 | 1212022212002220102200101100 |
4 | 3032311323012030102201 |
5 | 3330341000133100413 |
6 | 50121512314225013 |
7 | 2664635642350122 |
oct | 316657306142241 |
9 | 55285086380340 |
10 | 14214112003233 |
11 | 459019773477a |
12 | 1716959425169 |
13 | 7c1500b3909c |
14 | 371d76860049 |
15 | 199b1d22ba73 |
hex | ced7b18c4a1 |
14214112003233 has 6 divisors (see below), whose sum is σ = 20531495115794. Its totient is φ = 9476074668816.
The previous prime is 14214112003199. The next prime is 14214112003319. The reversal of 14214112003233 is 33230021141241.
14214112003233 is a `hidden beast` number, since 1 + 4 + 21 + 411 + 200 + 3 + 23 + 3 = 666.
14214112003233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 12960950417424 + 1253161585809 = 3600132^2 + 1119447^2 .
It is not a de Polignac number, because 14214112003233 - 221 = 14214109906081 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14214112003197 and 14214112003206.
It is not an unprimeable number, because it can be changed into a prime (14214112003733) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 789672889060 + ... + 789672889077.
Almost surely, 214214112003233 is an apocalyptic number.
It is an amenable number.
14214112003233 is a deficient number, since it is larger than the sum of its proper divisors (6317383112561).
14214112003233 is a wasteful number, since it uses less digits than its factorization.
14214112003233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1579345778143 (or 1579345778140 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 14214112003233 its reverse (33230021141241), we get a palindrome (47444133144474).
The spelling of 14214112003233 in words is "fourteen trillion, two hundred fourteen billion, one hundred twelve million, three thousand, two hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •