Base | Representation |
---|---|
bin | 1100111011010111101100… |
… | …1010100001111001011001 |
3 | 1212022212002222120110011102 |
4 | 3032311323022201321121 |
5 | 3330341000430442223 |
6 | 50121512354441145 |
7 | 2664635655124202 |
oct | 316657312417131 |
9 | 55285088513142 |
10 | 14214113140313 |
11 | 4590198341009 |
12 | 17169598931b5 |
13 | 7c1501146808 |
14 | 371d76a785a9 |
15 | 199b1d3a3928 |
hex | ced7b2a1e59 |
14214113140313 has 8 divisors (see below), whose sum is σ = 14237374018560. Its totient is φ = 14190869515680.
The previous prime is 14214113140207. The next prime is 14214113140349. The reversal of 14214113140313 is 31304131141241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14214113140313 - 230 = 14213039398489 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14214113140363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2663873 + ... + 5960238.
It is an arithmetic number, because the mean of its divisors is an integer number (1779671752320).
Almost surely, 214214113140313 is an apocalyptic number.
It is an amenable number.
14214113140313 is a deficient number, since it is larger than the sum of its proper divisors (23260878247).
14214113140313 is an equidigital number, since it uses as much as digits as its factorization.
14214113140313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8626807.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 14214113140313 its reverse (31304131141241), we get a palindrome (45518244281554).
The spelling of 14214113140313 in words is "fourteen trillion, two hundred fourteen billion, one hundred thirteen million, one hundred forty thousand, three hundred thirteen".
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