142141343141241 has 6 divisors (see below), whose sum is σ = 205315273426250. Its totient is φ = 94760895427488.

The previous prime is 142141343141219. The next prime is 142141343141279.

142141343141241 is a `hidden beast` number, since 1 + 4 + 2 + 141 + 3 + 431 + 41 + 2 + 41 = 666.

142141343141241 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in only one way, i.e., 138626393108841 + 3514950032400 = 11773971^2 + 1874820^2 .

It is not a de Polignac number, because 142141343141241 - 2⁵ = 142141343141209 is a prime.

It is a super-2 number, since 2×142141343141241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142141343141196 and 142141343141205.

It is not an unprimeable number, because it can be changed into a prime (142141343146241) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7896741285616 + ... + 7896741285633.

Almost surely, 2^{142141343141241} is an apocalyptic number.

It is an amenable number.

142141343141241 is a deficient number, since it is larger than the sum of its proper divisors (63173930285009).

142141343141241 is a wasteful number, since it uses less digits than its factorization.

142141343141241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15793482571255 (or 15793482571252 counting only the distinct ones).

The product of its digits is 36864, while the sum is 36.

The spelling of 142141343141241 in words is "one hundred forty-two trillion, one hundred forty-one billion, three hundred forty-three million, one hundred forty-one thousand, two hundred forty-one".