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14214214244411 = 35677398413943
BaseRepresentation
bin1100111011011000000100…
…1100001101100000111011
31212022212101000211001220122
43032312001030031200323
53330341202321310121
650121530405443455
72664641323365266
oct316660114154073
955285330731818
1014214214244411
11459023a417015
12171698771058b
137c1519085a1c
14371d86275cdd
15199b271c55ab
hexced8130d83b

14214214244411 has 4 divisors (see below), whose sum is σ = 14214612694032. Its totient is φ = 14213815794792.

The previous prime is 14214214244389. The next prime is 14214214244431. The reversal of 14214214244411 is 11444241241241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14214214244411 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14214214244431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 199171295 + ... + 199242648.

It is an arithmetic number, because the mean of its divisors is an integer number (3553653173508).

Almost surely, 214214214244411 is an apocalyptic number.

14214214244411 is a deficient number, since it is larger than the sum of its proper divisors (398449621).

14214214244411 is an equidigital number, since it uses as much as digits as its factorization.

14214214244411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 398449620.

The product of its digits is 32768, while the sum is 35.

Adding to 14214214244411 its reverse (11444241241241), we get a palindrome (25658455485652).

The spelling of 14214214244411 in words is "fourteen trillion, two hundred fourteen billion, two hundred fourteen million, two hundred forty-four thousand, four hundred eleven".

Divisors: 1 35677 398413943 14214214244411