14214413124113 has 4 divisors (see below), whose sum is σ = 14214421784628. Its totient is φ = 14214404463600.

The previous prime is 14214413124077. The next prime is 14214413124151. The reversal of 14214413124113 is 31142131441241.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 8983165879249 + 5231247244864 = 2997193^2 + 2287192^2 .

It is a cyclic number.

It is not a de Polignac number, because 14214413124113 - 2²⁴ = 14214396346897 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 14214413124113.

It is not an unprimeable number, because it can be changed into a prime (14214413126113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1029806 + ... + 5430407.

It is an arithmetic number, because the mean of its divisors is an integer number (3553605446157).

Almost surely, 2^{14214413124113} is an apocalyptic number.

It is an amenable number.

14214413124113 is a deficient number, since it is larger than the sum of its proper divisors (8660515).

14214413124113 is an equidigital number, since it uses as much as digits as its factorization.

14214413124113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8660514.

The product of its digits is 9216, while the sum is 32.

Adding to 14214413124113 its reverse (31142131441241), we get a palindrome (45356544565354).

The spelling of 14214413124113 in words is "fourteen trillion, two hundred fourteen billion, four hundred thirteen million, one hundred twenty-four thousand, one hundred thirteen".