Base | Representation |
---|---|
bin | 10100101011110100101… |
… | …110110111010000010011 |
3 | 12000212222221210102222022 |
4 | 110223310232313100103 |
5 | 141242104423231311 |
6 | 3005000342202055 |
7 | 204460510164446 |
oct | 24536456672023 |
9 | 5025887712868 |
10 | 1421445133331 |
11 | 4a89167a2383 |
12 | 1ab59b12332b |
13 | a4070803492 |
14 | 4cb267d165d |
15 | 26e95bd85db |
hex | 14af4bb7413 |
1421445133331 has 2 divisors, whose sum is σ = 1421445133332. Its totient is φ = 1421445133330.
The previous prime is 1421445133247. The next prime is 1421445133343. The reversal of 1421445133331 is 1333315441241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1421445133331 - 210 = 1421445132307 is a prime.
It is a super-2 number, since 2×14214451333312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1421445133291 and 1421445133300.
It is not a weakly prime, because it can be changed into another prime (1421445133351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710722566665 + 710722566666.
It is an arithmetic number, because the mean of its divisors is an integer number (710722566666).
Almost surely, 21421445133331 is an apocalyptic number.
1421445133331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421445133331 is an equidigital number, since it uses as much as digits as its factorization.
1421445133331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 35.
The spelling of 1421445133331 in words is "one trillion, four hundred twenty-one billion, four hundred forty-five million, one hundred thirty-three thousand, three hundred thirty-one".
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