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14215050193 is a prime number
BaseRepresentation
bin11010011110100100…
…00111001111010001
31100200200010100222111
431033102013033101
5213103023101233
610310313505321
71012155635011
oct151722071721
940620110874
1014215050193
116035030673
122908712241
131457035606
1498bc95c41
15582e61acd
hex34f4873d1

14215050193 has 2 divisors, whose sum is σ = 14215050194. Its totient is φ = 14215050192.

The previous prime is 14215050169. The next prime is 14215050233. The reversal of 14215050193 is 39105051241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9058661329 + 5156388864 = 95177^2 + 71808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14215050193 is a prime.

It is not a weakly prime, because it can be changed into another prime (14215050593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107525096 + 7107525097.

It is an arithmetic number, because the mean of its divisors is an integer number (7107525097).

Almost surely, 214215050193 is an apocalyptic number.

It is an amenable number.

14215050193 is a deficient number, since it is larger than the sum of its proper divisors (1).

14215050193 is an equidigital number, since it uses as much as digits as its factorization.

14215050193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

The spelling of 14215050193 in words is "fourteen billion, two hundred fifteen million, fifty thousand, one hundred ninety-three".