Base | Representation |
---|---|
bin | 1100111011011011011000… |
… | …1001001110101001001011 |
3 | 1212022221122221112000012102 |
4 | 3032312312021032221023 |
5 | 3330400012234430201 |
6 | 50122154503304015 |
7 | 2665002331634624 |
oct | 316666611165113 |
9 | 55287587460172 |
10 | 14215102655051 |
11 | 4590655953091 |
12 | 1716b9514b00b |
13 | 7c162b1522ac |
14 | 37202c256a4b |
15 | 199b7a1b326b |
hex | cedb624ea4b |
14215102655051 has 4 divisors (see below), whose sum is σ = 14215133013432. Its totient is φ = 14215072296672.
The previous prime is 14215102655041. The next prime is 14215102655059. The reversal of 14215102655051 is 15055620151241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14215102655051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14215102654996 and 14215102655014.
It is not an unprimeable number, because it can be changed into a prime (14215102655059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14465645 + ... + 15417038.
It is an arithmetic number, because the mean of its divisors is an integer number (3553783253358).
Almost surely, 214215102655051 is an apocalyptic number.
14215102655051 is a deficient number, since it is larger than the sum of its proper divisors (30358381).
14215102655051 is an equidigital number, since it uses as much as digits as its factorization.
14215102655051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30358380.
The product of its (nonzero) digits is 60000, while the sum is 38.
The spelling of 14215102655051 in words is "fourteen trillion, two hundred fifteen billion, one hundred two million, six hundred fifty-five thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.132 sec. • engine limits •