14215354221402 has 12 divisors (see below), whose sum is σ = 30799934146410. Its totient is φ = 4738451407128.

The previous prime is 14215354221401. The next prime is 14215354221413. The reversal of 14215354221402 is 20412245351241.

14215354221402 is a `hidden beast` number, since 1 + 4 + 2 + 1 + 53 + 542 + 21 + 40 + 2 = 666.

14215354221402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 14195631108681 + 19723112721 = 3767709^2 + 140439^2 .

It is a super-3 number, since 3×14215354221402³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (14215354221401) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 394870950577 + ... + 394870950612.

Almost surely, 2^{14215354221402} is an apocalyptic number.

14215354221402 is an abundant number, since it is smaller than the sum of its proper divisors (16584579925008).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14215354221402 is a wasteful number, since it uses less digits than its factorization.

14215354221402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 789741901197 (or 789741901194 counting only the distinct ones).

The product of its (nonzero) digits is 76800, while the sum is 36.

Adding to 14215354221402 its reverse (20412245351241), we get a palindrome (34627599572643).

The spelling of 14215354221402 in words is "fourteen trillion, two hundred fifteen billion, three hundred fifty-four million, two hundred twenty-one thousand, four hundred two".