Base | Representation |
---|---|
bin | 11010011110101100… |
… | …10001100101001011 |
3 | 1100200202011210110121 |
4 | 31033112101211023 |
5 | 213103313004011 |
6 | 10310353124111 |
7 | 1012201130413 |
oct | 151726214513 |
9 | 40622153417 |
10 | 14216141131 |
11 | 6035706275 |
12 | 2908b59637 |
13 | 145732803a |
14 | 98c09b643 |
15 | 5830c9e71 |
hex | 34f59194b |
14216141131 has 2 divisors, whose sum is σ = 14216141132. Its totient is φ = 14216141130.
The previous prime is 14216141123. The next prime is 14216141153. The reversal of 14216141131 is 13114161241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14216141131 - 23 = 14216141123 is a prime.
It is a super-2 number, since 2×142161411312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14216141096 and 14216141105.
It is not a weakly prime, because it can be changed into another prime (14216141101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7108070565 + 7108070566.
It is an arithmetic number, because the mean of its divisors is an integer number (7108070566).
Almost surely, 214216141131 is an apocalyptic number.
14216141131 is a deficient number, since it is larger than the sum of its proper divisors (1).
14216141131 is an equidigital number, since it uses as much as digits as its factorization.
14216141131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 25.
The spelling of 14216141131 in words is "fourteen billion, two hundred sixteen million, one hundred forty-one thousand, one hundred thirty-one".
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