Base | Representation |
---|---|
bin | 1100111011101101101010… |
… | …1001101100110101100010 |
3 | 1212100102022221202202212011 |
4 | 3032323122221230311202 |
5 | 3330440040042130102 |
6 | 50124325451223134 |
7 | 2665235051435401 |
oct | 316733251546542 |
9 | 55312287682764 |
10 | 14220010114402 |
11 | 4592743aa3a14 |
12 | 1717b24747aaa |
13 | 7c1c30a7c6b1 |
14 | 372375d09638 |
15 | 199d65e3a2d7 |
hex | ceedaa6cd62 |
14220010114402 has 4 divisors (see below), whose sum is σ = 21330015171606. Its totient is φ = 7110005057200.
The previous prime is 14220010114393. The next prime is 14220010114439. The reversal of 14220010114402 is 20441101002241.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13359529394761 + 860480719641 = 3655069^2 + 927621^2 .
It is a super-2 number, since 2×142200101144022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3555002528599 + ... + 3555002528602.
Almost surely, 214220010114402 is an apocalyptic number.
14220010114402 is a deficient number, since it is larger than the sum of its proper divisors (7110005057204).
14220010114402 is an equidigital number, since it uses as much as digits as its factorization.
14220010114402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7110005057203.
The product of its (nonzero) digits is 512, while the sum is 22.
Adding to 14220010114402 its reverse (20441101002241), we get a palindrome (34661111116643).
The spelling of 14220010114402 in words is "fourteen trillion, two hundred twenty billion, ten million, one hundred fourteen thousand, four hundred two".
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