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14220100402003 is a prime number
BaseRepresentation
bin1100111011101110000000…
…0010000111101101010011
31212100102120020122212011101
43032323200002013231103
53330440231200331003
650124342434325231
72665240226036506
oct316734002075523
955312506585141
1014220100402003
11459278aa61371
121717b4aa29817
137c1c466a2502
14372383ccd13d
15199d6dd2211d
hexceee0087b53

14220100402003 has 2 divisors, whose sum is σ = 14220100402004. Its totient is φ = 14220100402002.

The previous prime is 14220100401959. The next prime is 14220100402037. The reversal of 14220100402003 is 30020400102241.

14220100402003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14220100402003 - 221 = 14220098304851 is a prime.

It is a super-2 number, since 2×142201004020032 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14220100400003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110050201001 + 7110050201002.

It is an arithmetic number, because the mean of its divisors is an integer number (7110050201002).

Almost surely, 214220100402003 is an apocalyptic number.

14220100402003 is a deficient number, since it is larger than the sum of its proper divisors (1).

14220100402003 is an equidigital number, since it uses as much as digits as its factorization.

14220100402003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 14220100402003 its reverse (30020400102241), we get a palindrome (44240500504244).

The spelling of 14220100402003 in words is "fourteen trillion, two hundred twenty billion, one hundred million, four hundred two thousand, three".