Base | Representation |
---|---|
bin | 1100111011101110000000… |
… | …0010000111101101010011 |
3 | 1212100102120020122212011101 |
4 | 3032323200002013231103 |
5 | 3330440231200331003 |
6 | 50124342434325231 |
7 | 2665240226036506 |
oct | 316734002075523 |
9 | 55312506585141 |
10 | 14220100402003 |
11 | 459278aa61371 |
12 | 1717b4aa29817 |
13 | 7c1c466a2502 |
14 | 372383ccd13d |
15 | 199d6dd2211d |
hex | ceee0087b53 |
14220100402003 has 2 divisors, whose sum is σ = 14220100402004. Its totient is φ = 14220100402002.
The previous prime is 14220100401959. The next prime is 14220100402037. The reversal of 14220100402003 is 30020400102241.
14220100402003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14220100402003 - 221 = 14220098304851 is a prime.
It is a super-2 number, since 2×142201004020032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14220100400003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110050201001 + 7110050201002.
It is an arithmetic number, because the mean of its divisors is an integer number (7110050201002).
Almost surely, 214220100402003 is an apocalyptic number.
14220100402003 is a deficient number, since it is larger than the sum of its proper divisors (1).
14220100402003 is an equidigital number, since it uses as much as digits as its factorization.
14220100402003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 14220100402003 its reverse (30020400102241), we get a palindrome (44240500504244).
The spelling of 14220100402003 in words is "fourteen trillion, two hundred twenty billion, one hundred million, four hundred two thousand, three".
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