Base | Representation |
---|---|
bin | 1100111011101110100100… |
… | …1101110001011101010011 |
3 | 1212100102221222112101101202 |
4 | 3032323221031301131103 |
5 | 3330441040114422124 |
6 | 50124410020221415 |
7 | 2665244106323513 |
oct | 316735115613523 |
9 | 55312858471352 |
10 | 14220254451539 |
11 | 4592859a0a034 |
12 | 1717b9253a86b |
13 | 7c1c6c58b696 |
14 | 37239a54d843 |
15 | 199d7c6015ae |
hex | ceee9371753 |
14220254451539 has 2 divisors, whose sum is σ = 14220254451540. Its totient is φ = 14220254451538.
The previous prime is 14220254451499. The next prime is 14220254451547. The reversal of 14220254451539 is 93515445202241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14220254451539 - 216 = 14220254386003 is a prime.
It is a super-3 number, since 3×142202544515393 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14220254451493 and 14220254451502.
It is not a weakly prime, because it can be changed into another prime (14220254451239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110127225769 + 7110127225770.
It is an arithmetic number, because the mean of its divisors is an integer number (7110127225770).
Almost surely, 214220254451539 is an apocalyptic number.
14220254451539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14220254451539 is an equidigital number, since it uses as much as digits as its factorization.
14220254451539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728000, while the sum is 47.
The spelling of 14220254451539 in words is "fourteen trillion, two hundred twenty billion, two hundred fifty-four million, four hundred fifty-one thousand, five hundred thirty-nine".
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